40. Combination Sum II
Description Given a collection of candidate numbers (candidates
) and a target number (target
), find all unique combinations in candidates
where the candidate numbers sum to target
.
Each number in candidates
may only be used once in the combination.
Note: The solution set must not contain duplicate combinations.
Example 1:
1 2 3 4 5 6 7 8 Input: candidates = [10,1,2,7,6,1,5], target = 8 Output: [ [1,1,6], [1,2,5], [1,7], [2,6] ]
Example 2:
1 2 3 4 5 6 Input: candidates = [2,5,2,1,2], target = 5 Output: [ [1,2,2], [5] ]
Constraints:
1 <=candidates.length <= 100
1 <=candidates[i] <= 50
1 <= target <= 30
Hints/Notes
2024/12/19
backtracking
review together with 3sum
No solution from 0x3F
Solution Language: C++
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 class Solution {public : vector<int > cur; vector<vector<int >> res; vector<vector<int >> combinationSum2 (vector<int >& candidates, int target) { sort (candidates.begin (), candidates.end ()); dfs (candidates, 0 , target); return res; } void dfs (vector<int >& candidates, int start, int target) { if (target == 0 ) { res.push_back (cur); return ; } if (target < 0 || start == candidates.size ()) { return ; } for (int i = start; i < candidates.size (); i++) { if (i > start && candidates[i] == candidates[i - 1 ]) { continue ; } if (candidates[i] > target) { break ; } cur.push_back (candidates[i]); dfs (candidates, i + 1 , target - candidates[i]); cur.pop_back (); } } };