572. Subtree of Another Tree

572. Subtree of Another Tree

Description

Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.

A subtree of a binary tree tree is a tree that consists of a node in tree and all of this node’s descendants. The tree tree could also be considered as a subtree of itself.

Example 1:

1
2
Input: root = [3,4,5,1,2], subRoot = [4,1,2]
Output: true

Example 2:

1
2
Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]
Output: false

Constraints:

  • The number of nodes in the root tree is in the range [1, 2000].
  • The number of nodes in the subRoot tree is in the range [1, 1000].
  • -10^4 <= root.val <= 10^4
  • -10^4 <= subRoot.val <= 10^4

Hints/Notes

Solution

Language: C++

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left),
* right(right) {}
* };
*/
class Solution {
public:
bool isSubtree(TreeNode* root, TreeNode* subRoot) {
if (!root && !subRoot) {
return true;
}
if (!root || !subRoot) {
return false;
}
bool ans = false;
if (root->val == subRoot->val) {
ans = validate(root, subRoot);
}
if (ans) {
return true;
} else {
return isSubtree(root->left, subRoot) ||
isSubtree(root->right, subRoot);
}
}

bool validate(TreeNode* root, TreeNode* subRoot) {
if (!root && !subRoot) {
return true;
}
if (!root || !subRoot) {
return false;
}
if (root->val != subRoot->val) {
return false;
}
return validate(root->left, subRoot->left) &&
validate(root->right, subRoot->right);
}
};