648. Replace Words

648. Replace Words

Description

Difficulty: Medium

Related Topics: Array, Hash Table, String, Trie

In English, we have a concept called root, which can be followed by some other word to form another longer word - let’s call this word successor. For example, when the root "an" is followed by the successor word "other", we can form a new word "another".

Given a dictionary consisting of many roots and a sentence consisting of words separated by spaces, replace all the successors in the sentence with the root forming it. If a successor can be replaced by more than one root, replace it with the root that has the shortest length.

Return the sentence after the replacement.

Example 1:

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Input: dictionary = ["cat","bat","rat"], sentence = "the cattle was rattled by the battery"
Output: "the cat was rat by the bat"

Example 2:

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Input: dictionary = ["a","b","c"], sentence = "aadsfasf absbs bbab cadsfafs"
Output: "a a b c"

Constraints:

  • 1 <= dictionary.length <= 1000
  • 1 <= dictionary[i].length <= 100
  • dictionary[i] consists of only lower-case letters.
  • 1 <= sentence.length <= 106
  • sentence consists of only lower-case letters and spaces.
  • The number of words in sentence is in the range [1, 1000]
  • The length of each word in sentence is in the range [1, 1000]
  • Every two consecutive words in sentence will be separated by exactly one space.
  • sentence does not have leading or trailing spaces.

Hints/Notes

  • Trie

Solution

Language: C++

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class Solution {
public:
struct TrieNode{
bool end;
vector<TrieNode*> children;
TrieNode() {
end = false;
children = vector<TrieNode*>(26, nullptr);
}
};

string replaceWords(vector<string>& dictionary, string sentence) {
TrieNode* root = new TrieNode();
for (string word : dictionary) {
TrieNode* head = root;
for (char c : word) {
if (!head->children[c - 'a']) {
head->children[c - 'a'] = new TrieNode();
}
head = head->children[c - 'a'];
}
head->end = true;
}
size_t pos = 0;
string word;
istringstream iss(sentence);
string res;
do {
string word;
iss >> word;
if (word == "") {
break;
}
TrieNode* head = root;
string newWord;
for (char c : word) {
if (!head) {
newWord = word;
break;
} else {
if (head->end) {
break;
} else {
head = head->children[c - 'a'];
newWord += c;
}
}
}
res = res == "" ? newWord : res + " " + newWord;
} while (iss);
return res;
}
};